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6u^2+66u-72=0
a = 6; b = 66; c = -72;
Δ = b2-4ac
Δ = 662-4·6·(-72)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-78}{2*6}=\frac{-144}{12} =-12 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+78}{2*6}=\frac{12}{12} =1 $
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